PAT 1018

题目 : Public Bike Management

分值 : 30
难度 : 难题
思路 : 最短路径解决不了,因为多层条件第二层不是贪心的,所以只能DFS+回溯了。
坑点 : 肯定是有很多的,但我没遇到,哈哈哈,我又用了递归倒叙打印。
评语 : 以前一直觉得是难题,很怕这题,这次动手一做,一次就AC太爽了。哈哈哈。

具体代码如下

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#include <iostream>
using namespace std ;
#define MAX_ 99999999
int Cmax , N ,Sp , M ;
int value[501] ;
int map[501][501] ;
int result[501] ;
int temp[501] ;
int flag[501] ;
int min_cost =MAX_ ;
int min_s_bike = MAX_ ;
int min_r_bike =MAX_ ;
int temp_cost ;
int temp_s_bike ;
int temp_r_bike ;
void dfs(int start ,int target)
{
if(start == target)
{ // 距离短 距离一样 发出的bike少 距离一样 且 送出的bike一样 但是回收的bike少
if(temp_cost < min_cost || (temp_cost == min_cost)&&(temp_s_bike< min_s_bike) || ((temp_cost == min_cost)&&(temp_s_bike== min_s_bike))&& (temp_r_bike < min_r_bike))
{
min_cost = temp_cost ;
min_r_bike = temp_r_bike ;
min_s_bike =temp_s_bike ;
for(int i = 0 ; i< 501 ;i++) //更优解路径保存
{
result[i] = temp[i] ;
}
}
return ;
}
for(int i = 1 ;i<= N ; i++) //遍历start 开始可能的 出发点;
{
if(map[start][i] != MAX_ && !flag[i] && start != i ) //start-> i 存在通路 且 i没被访问过
{
int olds , oldr ,oldc;
olds =temp_s_bike;
oldr = temp_r_bike ;
oldc = temp_cost ;
temp_cost += map[start][i] ;
int fix = value[i] - Cmax/2 ;

if(fix > 0 ) //就是说 i这个点富裕
temp_r_bike += fix ; //富裕的东西就要被带走
else
{
temp_r_bike += fix ; //receive 够用 send 不用多
if(temp_r_bike < 0) // receive 不够用 send 多起来 且 receive 清零
{
temp_s_bike -= temp_r_bike ;
temp_r_bike =0 ;
}

}
flag[i] = 1 ;
temp[i] = start;
dfs(i , target) ; //通过i这个节点 往下 深搜
flag[i] = 0 ;
temp[i] = 0;
temp_cost = oldc ;
temp_s_bike =olds;
temp_r_bike = oldr ;

}
}
return ;

}
void print(int cur)
{
if(cur!=0)
{
print(result[cur]) ;
cout <<"->"<<cur ;
}

}
int main() {
cin >> Cmax >> N >>Sp >> M ;
for(int i = 1; i <=N ; i++)
cin>>value[i];
for(int i = 0 ; i<=N ; i++)
for(int j = 0 ; j<=N ; j++)
if(i!=j)
map[i][j] =MAX_ ;
for(int i = 0 ; i< M ;i++)
{
int v1 ,v2 ,cost ;
cin >>v1 >> v2 >>cost ;
map[v1][v2] = cost ;
map[v2][v1] = cost ;
}
dfs(0,Sp);
cout<<min_s_bike <<" " ;
int cur = Sp ;
cout<<"0" ;
print(Sp) ;
cout <<" "<<min_r_bike <<endl;

}
}

第二次重做时的代码

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#include <iostream>
#include <vector>
#define Max_ 999999999
using namespace std;
vector<int> db ;
vector<int> ans;
vector<int> temp_ans ;
int Map[501][501];
int Cmax , N , Sp , M;
bool flag[501] ;
int min_dict =Max_ , mini_sent = Max_ , mini_back =Max_ ;
void Dfs(int pos , int target , int dict ,int sent_bike , int back_bike )
{
if(pos==target)
{
if(dict < min_dict)
{
min_dict = dict ;
mini_sent = sent_bike ;
mini_back = back_bike ;
ans = temp_ans;
}
else if(dict == min_dict ){
if(sent_bike < mini_sent)
{
mini_sent = sent_bike ;
mini_back = back_bike ;
ans = temp_ans;
}
else if(sent_bike == mini_sent && back_bike < mini_back)
{
mini_sent = sent_bike ;
mini_back = back_bike ;
ans = temp_ans;
}
}
return ;
}
for(int i = 1 ; i<= N ; i++)
{
if(flag[i] || Map[pos][i] == Max_ || pos == i ) continue ;
temp_ans.push_back(i) ;
flag[i] = true;
int sent_ =sent_bike , back = back_bike +(db[i]-Cmax/2) ;
if( back < 0 )
{
sent_ -=( back_bike + (db[i]-Cmax/2) );
back= 0 ;
}
Dfs(i , target ,dict+Map[pos][i] ,sent_ ,back);
temp_ans.pop_back() ;
flag[i] = false ;
}
}
void init()
{
for(int i = 0 ;i< 501 ;i++)
for(int j= 0 ; j< 501;j++)
if(i!=j)
Map[i][j] = Max_ ;
}
int main()
{
int t ,c1 ,c2 ;
cin >> Cmax >> N >> Sp >> M ;
db.resize(N+1);
init();
for(int i = 1 ; i<= N ; i++)
{
cin >> t ;
db[i] = t ;
}
for(int i = 0 ; i< M ; i++)
{
cin >> c1 >> c2 >> t ;
Map[c1][c2] = t ;
Map[c2][c1] = t ;
}
Dfs( 0, Sp , 0 , 0, 0);
cout <<mini_sent <<" 0" ;
for(int i = 0 ;i < ans.size(); i++)
cout <<"->"<<ans[i];
cout <<" " <<mini_back<<endl ;
}